Q.

Find the condition for the lines joining the origin to the points of intersection of the circle x2 + y2 = a2 and the line lx + my =1 to coincide.

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Detailed Solution

 The given circle is x2+y2=a2(1)
 and the given line is lx+my=1(2)
Let A and B be the point of intersection of given line and circle.
By homogenizing the equation (1) with equation (2), we get combined equation of OA and OB is

x2+y2a2(1)2=0x2+y2a2(lx+my)2=0x2+y2a2l2x2+m2y2+2lmxy=0x2+y2a2l2x2a2m2y22a2lmxy=01a2l2x22a2lmxy+1a2m2y2=0.
Comparing equation (3) with 
Ax2+2Hxy+By2=0 we get
A=1a2l2 and 2H=2a2lmH=a2lm B=1a2m2
Given that (3) represents two coincident lines
then H2 = AB
a2lm2=1a2l21a2m2a4l2m2=1a2l2a2m2+a4l2m2a2l2+a2m2=1a2l2+m2=1
is the required condition

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