Find the condition under which a convex mirror can make a real image.

Substituting the sign of $f$ only in the mirror formula, we have$\frac{1}{v}+\frac{1}{u}=\frac{1}{+f}$

$\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$

For real image $v$ should be negative and for this $u$ should be positive and less than $f$. Object distance $u$ is positive means object should be virtual and lying between $P$ and $F$.

The ray diagram is as shown below.

Here $O$ = Virtual between $P$ and $F$

         $I$ = Real