Q.

 Find the correct answer based on the number of minimum carbons required for alkyne to show the corresponding isomerism

          

IsomerismMinimum number of carbons required
(i) Chain isomerism(a) 2
(ii) Positional isomerism(b) 3
(iii) Functional isomerism(c) 4
(iv) Ring chain isomerism(d) 5
(v) Optical isomerism(e) 6

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a

 (i)–(d); (ii)–(c); (iii)–(b); (iv)–(b); (v)–(e)

b

 (i)–(d); (ii)–(c); (iii)–(a); (iv)–(b); (v)–(e)

c

 (i)–(d); (ii)–(c); (iii)–(b); (iv)–(a); (v)–(e)

d

(i)–(a); (ii)–(b); (iii)–(c); (iv)–(d); (v)–(e)

     

answer is B.

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Detailed Solution

Alkynes must have minimum 5 carbons to show chain isomerism, 4 carbons to show positional isomerism, 3 carbons to show functional isomerism, 3 carbons to show Ring chain isomerism, and 6 carbons to show Optical isomerism

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