Find the Cube Root of a number $216$?

Prime factorization of $216$ is $2\times 2\times 2\times 3\times 3\times 3$

After simplifying the factors, we get

$2^3\times 3^3$

Further, we get

$6^3$

As a result of prime factorization, the cube root of $216$ is 

$={\left(2\times 2\times 2\times 3\times 3\times 3\right)}^{\frac{1}{3}}$

$=6$