Q.

Find the current and resistance drawn by a bulb rated 40 π‘Š; 220 𝑉, when it is connected to a 220 𝑉 supply. If the given bulb is replaced by a bulb if rating 25 π‘Š; 220 𝑉, will there be any change in the value of current and resistance? Justify your answer and determine the change.

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Detailed Solution

Case 1: power of bulb, P = 40 watt 

The voltage supplied across the bulb, 𝑉 = 220𝑉 

We know, power supplied by bulb, 𝑃 = 𝑉𝐼

or, 40 = 220 Γ— 𝐼

β‡’Current 𝐼 = 40/220 = 2/11 = 0. 18 π΄π‘šπ‘ 

Again, using the formula, 𝑃 = 𝑉²/𝑅 to find resistance of bulb

or, 𝑅 = 𝑉²/𝑃 

⇒𝑅 = (220)Β²/40 = 48400/40 = 1210 π‘œβ„Žπ‘š

Case 2: if the given bulb is replaced by a bulb operating 25 π‘Š; 220 V

Current, 𝐼' = 𝑃'/𝑉 = 25/220 = 0. 1136 π΄π‘šπ‘ 

resistance, 𝑅' = 𝑉²/𝑃' = (220)Β²/25 = 1936 π‘œβ„Žπ‘š. 

When we change the bulb, current and resistance will be changed. 

Change in current = 𝐼 βˆ’ 𝐼' = 0. 18 βˆ’ 0. 1136 = 0. 0664 π΄π‘šπ‘ 

The current decreases when we use 25 watt bulb in place of 40 watt bulb. 

Change in resistance = 1936 βˆ’ 1210 = 726 π‘œβ„Žπ‘š

 The resistance increase when we use 25 watt bulb in place of 40 watt.

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