Find the curved surface area of a frustum cone whose larger and smaller radius is 35 m and 10 m. The slant height is 45 m. (Use π=3 )

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6,375m2

6,275m2

6,075m2

6,175m2

answer is C.

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Detailed Solution

The curved surface area of a frustum is given by the formula,
CSA = πl(R+r)
where R= radius of the bigger circle, r = radius of the smaller circle, l = slant height of the cone.
In this question, we are given that smaller radius is 10 m, r = 10 m
Bigger radius is 35 m, R = 35 m
And slant height is 45 m, l = 45 m
⇒CSA = 3×45(35+10)
CSA = 3×45×45
CSA = 6075m2
So curved surface area of the given frustum is 6075 m2
So, the correct answer is “Option 3”.

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