Find the degree of the following polynomial. $\sqrt{3}{\mathrm{x}}^3+19\mathrm{x}+14$

To find the degree of a polynomial, look for the highest power of the variable present in the polynomial.

Given the polynomial: 

$\sqrt{3}{\mathrm{x}}^3+19\mathrm{x}+14$

The terms are:

1. $\sqrt{3}{\mathrm{x}}^3$– This term has a degree of 3 because of the ${\mathrm{x}}^3$.
2. 19x – This term has a degree of 1 because of the x.
3. 14 – This term is a constant and therefore has a degree of 0.

The highest degree term is $\sqrt{3}{\mathrm{x}}^3$ with a degree of 3.

Hence, the degree of the polynomial $\sqrt{\mathbf{3}}{\mathbf{x}}^{\mathbf{3}}\mathbf{+}\mathbf{19}\mathbf{x}\mathbf{+}\mathbf{14}$.