Find the dipole moment of system where the potential $2.0\times {10}^{-5}V$ at a point P, 0.1m from the dipole is $3.0\times {10}^4.\left(Use\theta ={30}^0\right).$ 

$\text{V}=\frac{kP\cos \theta }{r^2}$

$\frac{V{r}^2}{k\cos \theta }=qd=\frac{(2.0\times {10}^{-5}V){\left(0.1\right)}^2}{\{9.0\times {10}^9\frac{m}{\left(\frac{C}{V}\right)}\}\left(\frac{\sqrt{3}}{2}\right)}=2.57\times {10}^{-17}Cm$ 

Note that the units cancel to leave units appropriate for a dipole moment