Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Find the discriminant for the given quadratic equation, $x^{2} + 4 x + k = 0$ .

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

6 - 4 k

16 - 4 k

16 - 3 k

13 - 2 k

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

It is given that the quadratic equation,

x^{2} + 4 x + k = 0

.
One has to write the values of the coefficients of x and x² and c to find out the value of the discriminant.
Comparing the values of the given equation with standard quadratic equation,

{ax}^{2} + bx + c

we get the values of a, b, c as

a = 1, b = 4, c = k

.
Substituting the given values in the discriminant formula,

b^{2} - 4 ac

\Rightarrow D = (4)^{2} - 4 (1) (k)

∴ D = 16 - 4 k

Hence, the correct option is 2.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!