Find the discriminant of the quadratic equation:  $3\sqrt{3}{\mathrm{x}}^{\mathrm{𝟐}}+10\mathrm{x}+\sqrt{3}=\mathrm{𝟎}$. 

For the quadratic equation ax² + bx + c = 0, 

Discriminant = D = b² − 4ac 

Hence, for the given equation, D = ${10}^2-4\left(3\sqrt[ ]{3}\right)\sqrt[ ]{3}$ 

= 100 − 36  = 64 

Thus, the discriminant of the given equation is 64.