Find the distance between (3, 4) and (8, 16).

To find the distance between two points , we can use distance formula:

d =  $\sqrt{({\mathrm{x}}_2-{\mathrm{x}}_1{)}^{2 }+{({\mathrm{y}}_2-{\mathrm{y}}_1)}^2 }$

Where $(x_1, y_1) and (x_2,y_2)$coordinates of two points.

Given points are (3, 4) and (8, 16). 

Here, $(x_1, y_1) = (3, 4) and (x_2,y_2) = (8, 16)$

On substitution, we get: 

$\mathrm{d}=\sqrt{{\left(8-3\right)}^2+{\left(16-4\right)}^2}$

$\mathrm{d}=\sqrt{{\left(5\right)}^2+{\left(12\right)}^2}$

$\mathrm{d}=\sqrt{25+144}$

$\mathrm{d}=\sqrt{169}$

$\mathrm{d}=13$
Therefore the distance between given points is 13 units.