Find the distance between the points (-2, 3), and (5, 6).

The given two points are $\left({\mathrm{x}}_1,{\mathrm{y}}_1\right)=(-2,3),$and $\left({\mathrm{x}}_2,{\mathrm{y}}_{2 }\right)=(5,6)$

Using the Distance Formula $=\sqrt{{\left({\mathrm{x}}_2-{\mathrm{x}}_1\right)}^2+{\left({\mathrm{y}}_2-{\mathrm{y}}_1\right)}^2}$

On substitution, we get:

$=\sqrt{{\left(5-(-2)\right)}^2+{\left(6-3\right)}^2}$

$=\sqrt{{\left(7\right)}^2+{\left(3\right)}^2}$

$=\sqrt{49+9}$

$=\sqrt{58}$

 Therefore, the distance between the two points is $\sqrt{58}$ units.