Find the distance of the z-axis from the image of the point M(2,-3,3) in the plane x - 2y - z + 1 = 0

If image of point (2, - 3, 3) in the plane x - 2y - z + 1 = 0 is (a, b, c), then

$\frac{a-2}{1}=\frac{b+3}{-2}=\frac{c-3}{-1}=\frac{-2(2-2(-3)-3+1)}{{\left(1\right)}^2+{(-2)}^2+{(-1)}^2}=-2$

Hence, the image is (0, 1, 5)
Obviously distance of image of the point from the z-axis is 1