Find the emf of the cell in which the following reaction takes place at 298 KNi(s)+2Ag+(0.001M)→Ni2+(0.001M)+2Ag(s) (Given that Ecell 0=10.5V,2.303RTF=0.059 at 298K )

2 is correct answer if Ecell 0=1.05V (from the given data there no answer).E=1.05−0.05912log ⁡10−310−32=0.9615V.

Find the emf of the cell in which the following reaction takes place at 298 KNi(s)+2Ag+(0.001M)→Ni2+(0.001M)+2Ag(s) (Given that Ecell 0=10.5V,2.303RTF=0.059 at 298K )

2 is correct answer if Ecell 0=1.05V (from the given data there no answer).E=1.05−0.05912log ⁡10−310−32=0.9615V.

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Find the emf of the cell in which the following reaction takes place at 298 K
$Ni (s) + 2 {Ag}^{+} (0 .001 M) \to {Ni}^{2 +} (0 .001 M) + 2 Ag (s)$
$(Given that E_{cell}^{0} = 10 .5 V, \frac{2 .303 RT}{F} = 0 .059 at 298 K)$

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1.0385 V

1.05 V

0.9615 V

1.385 V

answer is B.

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2 is correct answer if $E_{cell}^{0} = 1 .05 V$ (from the given data there no answer).
$\begin{array}{l} E = 1 .05 - \frac{0 .0591}{2} \log \frac{10^{- 3}}{{(10^{- 3})}^{2}} \\ = 0 .9615 V . \end{array}$

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Find the emf of the cell in which the following reaction takes place at 298 KNi(s)+2Ag+(0.001M)→Ni2+(0.001M)+2Ag(s) (Given that Ecell 0=10.5V,2.303RTF=0.059 at 298K )

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Find the emf of the cell in which the following reaction takes place at 298 K
$Ni (s) + 2 {Ag}^{+} (0 .001 M) \to {Ni}^{2 +} (0 .001 M) + 2 Ag (s)$
$(Given that E_{cell}^{0} = 10 .5 V, \frac{2 .303 RT}{F} = 0 .059 at 298 K)$