Find the equation of a line perpendicular to $2x - 3y - 5 = 0$and cutting an intercept $1$ on the $x-$axis. 

Equation of any line perpendicular to $2x - 3y- 5 = 0$ is $-3x - 2y+k = 0$ which is passing through $(1, 0).$

Therefore,$-3 + 0 + k = 0$

$\Rightarrow k=-3$

Hence, the equation of the line is $3x + 2y + 3 = 0$