Find the equation of the cirlce of which points (4, 2), (1, 5) are the end points of a diameter.

Given points A = (4, 2), B = (1, 5)
$\text{ Eq: of circle with }\overline{\mathrm{AB}}\text{ as diameter is }$
$\begin{array}{l}\left(\mathrm{x}-{\mathrm{x}}_1\right)\left(\mathrm{x}-{\mathrm{x}}_2\right)+\left(\mathrm{y}-{\mathrm{y}}_1\right)\left(\mathrm{y}-{\mathrm{y}}_2\right)=0\\ (\mathrm{x}-4)(\mathrm{x}-1)+(\mathrm{y}-2)(\mathrm{y}-5)=0\\ {\mathrm{x}}^2+{\mathrm{y}}^2-5\mathrm{x}-7\mathrm{y}+14=0\end{array}$