Find the equation of the plane whose intercepts on X, Y, Z axes are 1, 2, 4 respectively.

Given X – intercept a = 1;
Y – intercept b = 2;
Z – intercept c = 4
Equation of plane in intercept form is
$\begin{array}{l}\frac{\mathrm{x}}{\mathrm{a}}+\frac{\mathrm{y}}{\mathrm{b}}+\frac{\mathrm{z}}{\mathrm{c}}=1\\ \Rightarrow \frac{\mathrm{x}}{1}+\frac{\mathrm{y}}{2}+\frac{\mathrm{z}}{4}=1\\ \Rightarrow \frac{4\mathrm{x}+2\mathrm{y}+\mathrm{z}}{4}=1\\ \Rightarrow 4\mathrm{x}+2\mathrm{y}+\mathrm{z}=4\end{array}$