Q.

Find the equation of the plane whose intercepts on X, Y, Z axes are 1, 2, 4 respectively.

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Detailed Solution

Given X – intercept a = 1;
Y – intercept b = 2;
Z – intercept c = 4
Equation of plane in intercept form is
xa+yb+zc=1x1+y2+z4=14x+2y+z4=14x+2y+z=4

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