Q.

Find the equation of the straight line parallel to the line 3x + 4y = 7 and passing through the point of intersection of the lines x – 2y – 3 = 0 and x + 3y – 6 = 0.

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Detailed Solution

Given lines
x+3y6=0 .....(1)x2y3=0 ....(2) 
Solve (1) & (2)
Point of intersection is (x,y)=215,35
 And given st.line 3x+4y=7
3x+4y7=0    ...(3)
Let the eq. of the straight line parallel to (3) and
 Passing through 215,35 be 
3x+4y+k=03215+435+k=0k=15  the eq'n of st.line is 3x+4y15=0 

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