Find the equivalent capacitance across A and B for the arrangement shown in figure. All the capacitors are of capacitance C

Three capacitors (consisting of two loops are short – circuited).

Effective capacitance of the rest of the circuit is 

${\mathrm{C}}_{\mathrm{eff}}={\left(\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{1}{\mathrm{C}}+\frac{2}{3\mathrm{C}}+\frac{1}{\mathrm{C}}\right)}^{-1}$

${\mathrm{C}}_{\mathrm{eff}}=\frac{3\mathrm{C}}{14}$