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Q.

Find the external work done by the system in kcal, when 20 kcal of heat is supplied to the system. The increase in the internal energy is 8400 J (J=4200J/kcal)

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a

16 kcal

b

20 kcal

c

19 kcal

d

18 kcal

answer is B.

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Detailed Solution

Given that dU=8400J ,

From the first law of thermodynamics, dQ=dU+dW  

dW=dQ−dU=84000−8400

=75600J

=756004.2cal

=18kcal

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