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Q.

Find the formula of halide of a metal whose successive ionization energies are x, 2x, 5x, 20x, 25x kJ $m o l^{- 1}$ respectively.

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a

$M_{2} X$

b

${MX}_{3}$

c

${MX}_{2}$

d

MX

answer is C.

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Detailed Solution

The biggest jump in successive ionization energy is from $I E_{3}$ to $I E_{4}$ . Hence, this element has 3 valence $e^{-}$

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