AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Find the greatest integer that divides 1251, 9377, and 15628 with remainders of 1, 2, and 3, respectively, using Euclid's division algorithm.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

450

200

625

125

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given that the remainders of 1251, 9377, and 15628 are 1, 2, and 3, respectively.
So, we will subtract the remainders from the given numbers.

⇒ 1251 − 1 = 1250 ⇒ 9377 − 2 = 9375,

⇒ 15628 − 3 = 15625.

To find the HCF of 15625, 9375, and 1250.
First, we will obtain the HCF of two numbers i.e. 15625 and 9395 by using Euclid’s division algorithm.

⇒ 15625 = 9375 × 1 + 6250 ⇒ 9375 = 6250 × 1 + 3125 ⇒ 6250 = 3125 × 2 + 0

Therefore, HCF

15625, 9375 = 3125.

Now, we will obtain the HCF of 3125 and 1250 by using Euclid’s division algorithm.

⇒ 3125 = 1250 × 1 + 625 ⇒ 1250 = 625 × 2 + 0

∴ HCF

1250, 9375, 15625 = 625

Hence, the correct option is 3.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!