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Q.

Find the greatest number that will divide 121, 33 and 55 leaving 1, 3 and 5 respectively, as remainder


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a

10

b

20

c

30

d

40 

answer is A.

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Detailed Solution

Given, numbers are 121, 33 and 55.
Here, 121, 33 and 55 leaving reminder 1, 3 and 5 respectively. So,
121-1=120
33-3=30
55-5=50
Factors of 120, 30 and 50,
120=2×2×2×3×5  30=2×3× 50=2×5×5   Thus, highest common factor, H.C.F 120,30,50=2×5=10 Thus, the greatest number is 10 which when divide 121, 33 and 55 gives 1 reminder, 3 and 5 respectively.
Option 1 is correct.
 
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