Find the greatest number that will divide 121, 33 and 55 leaving 1, 3 and 5 respectively, as remainder

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answer is A.

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Detailed Solution

Given, numbers are 121, 33 and 55.
Here, 121, 33 and 55 leaving reminder 1, 3 and 5 respectively. So,

121 - 1 = 120

33 - 3 = 30

55 - 5 = 50

Factors of 120, 30 and 50,

120 = 2 \times 2 \times 2 \times 3 \times 5

30 = 2 \times 3 \times

50 = 2 \times 5 \times 5

Thus, highest common factor,

H . C . F (120, 30, 50) = 2 \times 5 = 10

Thus, the greatest number is 10 which when divide 121, 33 and 55 gives 1 reminder, 3 and 5 respectively.
Option 1 is correct.

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