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Find the greatest number which on dividing 1657 and 2037 leaves a remainder of 6 and 5. respectively.

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123

127

235

305

answer is B.

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Detailed Solution

Required number = H.C.F. of (1657−6) and (2037−5)
Factor of 1651 = 13×127
Factor of 2032 = 2×2×2×2×127
∴ H.C.F. of 1651 and 2032 = 127

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