Find the greatest number which when divides 63, 121 and 208 leaves same remainder

Greatest number which when divides 63, 121 and 208 leaves same remainder

$\begin{array}{l}\mathrm{Re}mainder=R\\ 121-63\Rightarrow 58\\ 208-121\Rightarrow 87\\ 208-63\Rightarrow 145\\ \therefore HCFof58,87,145\end{array}$$\begin{array}{l}HCFof58,87\\ 58\left)87\right(1\\ 58\\ 29\left)58\right(2\\ 58\\ 0\\ HCF29,145\\ 29\left)145\right(5\\ 145\\ 0\\ \therefore HCFof63,121and208=29\end{array}$