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Q.

Find the half angular width of the central bright maximum in the Fraunhofer diffraction pattern of a slit of width  12×10−3 cm when the slit is illuminated by monochromatic light of wavelength 6000 A0.

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a

450

b

900

c

300

d

1800

answer is C.

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Detailed Solution

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Half angular width of the central maximum (θ),  ⇒sinθ= λa Put  a=12×10−3cm,  λ=6000A0=6×10−5cm ∴sinθ=λa=6×10−512×10−5=12 ⇒θ=300  

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