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Find the increases in temperature of aluminium rod it its length is to be increased by 1% $(α_{A l} = 25 \times 10^{- 6} /^{0} C)$

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100°C

400°C

300°C

600°C

answer is B.

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Detailed Solution

$α = \frac{l_{2} - l_{1}}{l_{1} (Δ t)} \Rightarrow \frac{1}{100 \times 25 \times 10^{- 6}} = 400^{0} C$

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