Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Find the largest five digit number that is divisible by 7,10,15,21 and 28 .


see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

  75758

b

-75758

c

-99960

d

  99960 

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution


Concept- In mathematics, the least common multiple is sometimes referred to as LCM or the lowest common multiple. The smallest number among all the common multiples of the provided numbers is the least common multiple of two or more numbers. Consider the integers 2 and 5. There will be different multiples for each. In order to solve the given question we have to check if number is divisible by all of these numbers, not just divide the number by LCM of these numbers.
Here, five digit largest number is 99999.
And, LCM of 7,10,15,21,28 is
7=7
10=2×5
15=3×5
21=3×7
28=2×2×7
Then,  2×2×3×5×7=420
Therefore 99999/420. the remainder is 39. therefore, 99999-39=99960
Here, remainder is 39
Then, 99999-39=99960
Hence, the  correct answer is 4) 99960.
 
Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Find the largest five digit number that is divisible by 7,10,15,21 and 28 .