Find the least number which should be added to 1456 so that is divisible by 6, 5 and 4 without leaving a remainder

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answer is D.

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Detailed Solution

LCM of $(6, 5, 4) = 60$

$60) 1456 (24 \frac{120}{256} \frac{240}{16}$

Number to be added $= (60 - 16) = 44$

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