Find the least number which when divided by 52, 78, 117 leaves remainders 33, 59 and 98 respectively.

Difference of 52 & 33 = 19

Difference of 78 & 59 = 19

Difference of 117 & 98 = 19

$\therefore \mathrm{Re}quirenumber=LCMof(52,78,117)-19$

$\Rightarrow LCMof52,78,117=468$

$Soleastnumberisrequired=468-19=449$