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Q.

Find the local maxima and local minima, if any, of the following functions. Find also the local maximum and the local minimum values as the case may be: g(x)=x2+2x,x>0


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a

1

b

2

c

3

d

4 

answer is B.

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Detailed Solution

g(x)=x2+2x
g`(x)=12-2x2
Put g`(x)=0
12-1x2=0
x=±2
Since x is given as greater than 0, so we get the value of x as 2 only.
g``(x)=4x3
g``(2)=423=12>0
Therefore 2 is the point of local minima by second derivative test.
Putting x = 2 in g(x) we get, g(2)=22+22=2
Hence, the local minimum value is 2.
 
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