Find the magnitude of magnetic moment of the current carrying loop ABCDEFA. Each side of the loop is 10cm long and current in the loop is  $i=2.0A$

$By assuming the equal and opposite currents in BE, two current carrying loops (ABEFA and BCDEB) are formed.$

$Their magnetic moments are equal in Magnitude but perpendicular to each other.$

$M_{net}=\sqrt{M^2+M^2}=\sqrt{2}M$

$here , M=IA=\left(2.0\right)\left(0.1\right)\left(0.1\right)=0.02$

$\Rightarrow M_{net}=\left(1.414\right)\left(0.02\right)=0.028A{m}^2$

$Their magnetic moments are equal in Magnitude but perpendicular to each other.$