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Find the mass M so that it remains at rest in the adjoining figure. Both the pulley and string are light and friction is absent everywhere. $(g = 10 m / s^{2})$ .

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4.8 kg

9 kg

2.5 kg

3 g

answer is A.

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Detailed Solution

In the figure shown,

$a = \frac{Net pulting force}{Total macs} = \frac{30 - 20}{3 + 2} = 2 m / s^{2}$

$2 kg, T - 20 = 2 \times a = 4 ∴ T = 24 N$

Find the mass `M` so that it remains at rest in the abjoining figure. Both the pulley and string are light and friction is absent everywhere. `(g = 10 - Sarthaks eConnect |

$M g = 2 T ∴ M = \frac{2 T}{g} = \frac{48}{10} ∴ = 4.8 kg$

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