Find the maximum number of identical bond angles in ${\mathrm{CH}}_2{\mathrm{F}}_2,{\mathrm{CCl}}_4,{\mathrm{XeF}}_4$and ${\mathrm{ClF}}_3$ respectively.

 

The maximum number of identical bond angles for the given molecule is,

${\mathrm{CH}}_2{\mathrm{F}}_2\to 4$

${\mathrm{CCl}}_4\to 6$

${\mathrm{XeF}}_4\to 4$

${\mathrm{ClF}}_3\to 2$

Bond angles for$\mathrm{F}-\mathrm{Xe}-\mathrm{F}$ bonds are 90 degrees, but bond angles for lone pairs are 180 degrees. The electrons in the molecule's plane are dispersed symmetrically because the fluorine atoms are at 90 degrees to one another.