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Find the mean deviation about the mean for the following data :

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2.09

2.08

2.07

2.06

answer is A.

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Detailed Solution

$M e a n \bar{x} = \frac{Σ f_{i} x_{i}}{Σ h} = \frac{18 + 40 + 105 + 225 + 88 + 52}{4 + 8 + 15 + 25 + 8 + 4}$

$= \frac{521}{66} = 8$

Now prepare the table given below :

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$Σ h = 66, Σ f_{i} | x_{i} - \bar{x} | = 138$

$∴ Mean deviation = \frac{\sum_{i = 1}^{6} f_{i} | x_{i} - \bar{x} |}{Σ f_{i}} = \frac{138}{66} = 2.09$

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