Find the median of the following distribution.
Class: 3-5-7-9-11-13
Frequency: 5 10 10 7 8

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8.0

8.10

8.15

8.20

answer is C.

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Detailed Solution

Class	Frequency(y)	Class mark(x)	yx
3-5	5	4	20
5-7	10	6	60
7-9	10	8	80
9-11	7	10	70
11-13	8	12	96
	∑ y = 326		∑ yx = 326

Class Mark =

\frac{Upper  class + lower class}{2}

Interval 3−5 ⇒

\frac{3 + 5}{2}

⇒ = 4 . So 4 is
Class mark of interval 3−5 and so on.
Step2:
We have the sigma of frequencies is 40 and sigma of yixi is 326 .
So, the mean of the given data is =

\frac{\sum yx}{\sum y}

After solving means 326 divided by 40, we get
=

\frac{326}{40}

The mean value is 8.15

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