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Q.

Find the median of the following distribution.

Class: 3-5-7-9-11-13

Frequency: 5 10 10 7 8

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a

      8.0

b

      8.10

c

      8.15

d

      8.20 

answer is C.

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Detailed Solution

Class

Frequency(y­­)

Class mark(x)

yx

3-5

5

4

20

5-7

10

6

60

7-9

10

8

80

9-11

7

10

70

11-13

8

12

96

 

∑ y = 326

 

∑ yx = 326

Class Mark =Upper  class + lower class2  Interval 3−5 ⇒ 3 + 52  = 4 . So 4 is
Class mark of interval 3−5 and so on.
 Step2:
We have the sigma of frequencies is 40 and sigma of yixi is 326 .
So, the mean of the given data is  =  yx y
After solving means 326 divided by 40, we get
 =32640
 The mean value is 8.15
 
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