Find the middle term (s) in the expansion of ${\left(\frac{3x}{7}-2y\right)}^{10}$

The given expansion is ${\left(\frac{3x}{7}-2y\right)}^{10}$ 

$n=10 is even$

Middle term $T_{\frac{n}{2}+1}=T_{5+1}$

${10}_{C_5}{\left(\frac{3x}{7}\right)}^5{\left(-2y\right)}^5=-{10}_{C_5}\frac{3^5{2}^5}{7^5}{x}^5{y}^5$

$-{10}_{C_5}{\left(\frac{3}{7}\right)}^5{2}^5. x^5{y}^5$

$\left(ii\right){\left[4a+\frac{3b}{2}\right]}^{11}; n=11 \left(odd\right)$

Middle terms $\frac{T_{n+1}}{2}; \frac{T_{n+3}}{2}=T_6, T_7$

$T_6=T_{5+1}={11}_{C_5}{\left(4a\right)}^6{\left(\frac{3b}{2}\right)}^5$

$T_7=T_{6+1}={11}_{C_6}{\left(4a\right)}^5{\left(\frac{3b}{2}\right)}^6$