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Find the minimum acceleration of the wedge so that block under free fall

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$g s e c θ$

$g c o t θ$

$g \tan θ$

$g \sin θ$

answer is B.

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Detailed Solution

$\begin{array}{l} f o r w e d g e x = \frac{1}{2} a t^{2} \to 1 \\ f o r b l o c k h = \frac{1}{2} g t^{2} \to 2 \\ \frac{x}{h} = \frac{a}{g} \Rightarrow a = g [\frac{x}{h}] b u t f r o m f i g \cot θ = \frac{x}{h} \\ ∴ a = g \cot θ \end{array}$

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