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Find the mode of the following frequency distribution.

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answer is B.

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Detailed Solution

Mode is the one which has the highest frequency
Here the class 30−40 has the highest frequency 16
Modal class is 30−40
Lower boundary of modal class is l=30
Height of each class is h=10−0=10
modal frequency is

f_{m}

=16
Frequency of class preceding to Modal class is

f_{1}

=10
Frequency of class succeeding to Modal class is

f_{2}

=12
Now, Mode=

(l + \frac{f_{m} - f_{1}}{2 f_{m} - f_{1} - f_{2}}) \times h

Putting the values,

(30 + \frac{16 - 10}{32 - 10 - 12}) \times 10 = 30 + 6 = 36

Hence (2) is the correct option.

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