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Q.

Find the modulation index of an AM wave having 8V variation where maximum amplitude of the AM wave is 9 V.

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a

0.1

b

0.8

c

0.2

d

0.5

answer is A.

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Detailed Solution

Modulation index $m = \frac{A_{m}}{A_{0}}$

${Given, 2A}_{m} = 8$

$\Rightarrow A_{m} = 4$

Also,
$\begin{array}{l} A_{m} + A_{c} = 9 \Rightarrow A_{c} = 5 \\ ∴ m = \frac{4}{5} = 0 .8 \end{array}$

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