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Find the molecular formula of a hydro carbon contains 85.7 % carbon & has molecular mass 84 is?

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$C_{6} H_{6}$

$C_{6} H_{15}$

$C_{6} H_{18}$

$C_{6} H_{12}$

answer is C.

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Detailed Solution

% C = 85.7 & H = 14.3
This data gives the E.F of compound tobe $C H_{2}$ [E.F mass = 14]
M.F = $E . F \times n = C H_{2} \times \frac{84}{14} = C_{6} H_{12}$

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