Find the nature of the roots of the following quadratic equation.

$2 x 2 − 3 x + 5 = 0$

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x = 0 and x = -2

x = 3, x = -6

No real root

None of these

answer is C.

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Detailed Solution

On comparing the equation with ax2 + bx + c = 0, we get
a = 2, b = -3 and c = 5
We know that, Discriminant = b2 – 4ac
= (– 3)2 – 4 (2) (5) = 9 – 40
= – 31
As you can see, b2 – 4ac < 0
Hence, no real root is possible for the given equation, 2x2 – 3x + 5 = 0.
Hence, Option (3) is the correct answer.

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