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Q.

Find the net deviation produced in the incident ray for the optical instrument shown in figure. (Take refractive index of the prism material as 2.) 

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a

66° CW

b

66° ACW

c

54° ACW

d

54° CW

answer is D.

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Detailed Solution

Deviation produced by the mirror is

δ1=π−2×60=60∘CW

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Deviation produced by the prism is

δ2=(1−2)×6=6∘ACW

 So, net deviation, δ=δ1+δ2=60∘−6∘CW=54∘CW

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