Find the next term in the alpha-numeric series:
Z1A,X2D,V6G,T21J,R88M,P445P,?

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

N2676S

N2676T

N2676N

N2670T

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

We will observe the pattern of this series.
first term of this series is starting with an alphabet
And, then alphabets are going in a decreasing order and there is a difference of 2 between each alphabet:
Z−2=X−2=V−2=T−2=R−2=P−2=N
Hence first letter of the next term will be N …(i)
The series is consisting of the numbers making a series of:
1,2,6,21,88,445,?
we can write this series as:
1,(1×1+1),(2×2+2),(6×3+3),(21×4+4),(88×5+5),?1,(1×1+1),(2×2+2),(6×3+3),(21×4+4),(88×5+5)
the next term will be: 445×6+6=2670+6=2676
Therefore, the next term will contain the number 2676 …(ii)
each term of this series is ending with an alphabet.
Alphabets are going in an ascending order and there is an addition of 3 to each preceding alphabet:
A+3=D+3=G+3=J+3=M+3=P+3=S
Hence, we can say that the required next term will end with the letter S ..(iii)
Hence, from (i),(ii) & (iii)
Our required next term of the series is
N2676S

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th