Find the ninth term of the arithmetic progression given below:

$3, 7, 10, 13, ...$

Given,

First term, $a = 3$

Common difference, $d = 7-3=4$

Number of terms, $n = 9$,

To find the  $9^{th}$ term, we can use the formula :

$a_n = a+(n-1)d$

By substituting the values, we get:

     $a_9=3+(9 -1) 4$

$\Rightarrow a_9=3+\left(8\right)\times 4$

$\Rightarrow a_9=3+32$

$\Rightarrow a_9=35$