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Find the number of bricks, each measuring 25 cm x 12. 5 cm x 7. 5 cm required to construct a wall 6m long, 5m high and 0.5m thick, while the cement and sand mixture occupies $\frac{1}{20}$ of the volume of the wall.

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6152

7542

3568

6080

answer is D.

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Detailed Solution

Given,
Measures of brick =25 cm x 12. 5 cm x 7. 5 cm
Dimension of the wall =6 m long, 5 m high and 0.5 m thick.
So, the volume of wall
= length X Height X thickness

= 6 \times 0.5 \times 5

= 15 m^{3}

Here, 1/20 fraction of volume of wall is occupied by the cement and sand mixture. Thus,
Wall volume which is occupied by bricks

(1 - \frac{1}{20})

volume of wall

= \frac{19}{20}

volume of the wall

= \frac{19}{20} \times 15 = 14.25 m^{3}

Volume of each brick can be given as,

= \frac{25}{100} m \times \frac{125}{1000} m \times \frac{75}{1000} m

So, total number of bricks can be calculated as,

= \frac{volume of wall}{volume of each brick}

= \frac{14.25 m^{3}}{\frac{25}{100} m \times \frac{125}{1000} m \times \frac{75}{1000} m}

= 6080

Thus, correct option is 4.

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