Q.

Find the number of compound which has four orbitals participating in bybridisation in central atom.

(a) K2CrO4    (b) K2Cr2O7

(c)  KMnO4      (d) K2MnO4

(e) Ni(CN)42     (f) NiCl4I2

(g) PtCl42     (h) Na4P2O7

(i) H2S2O8

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answer is 9.

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Detailed Solution

The hybridization of the given complex are, 

Question Image

 

 

 

 

All have 4 orbitals in hyb.

Hence correct answer is 0009

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