Find the number of compounds among the following whose hydrolysis is a non-redox reaction.

${\mathrm{XeF}}_2,{\mathrm{XeF}}_4,{\mathrm{XeF}}_6,\mathrm{Xe}{\mathrm{X}2\mathrm{X}2,\mathrm{XeOXe}, \mathrm{Xe}}_3$

The products of hydrolysis are ${\mathrm{XeOF}}_4$ and ${\mathrm{XeO}}_2{\mathrm{F}}_2$where the oxidation states of all the elements remain the same as it was in the reacting state.

$\begin{array}{l}{\mathrm{XeF}}_6+{\mathrm{H}}_2\mathrm{O}\to {\mathrm{XeOF}}_4+2\mathrm{HF}\\ \mathrm{XeO}+{\mathrm{H}}_2\mathrm{O}\to {\mathrm{XeO}}_2{\mathrm{F}}_2+2\mathrm{HF}\\ {\mathrm{XeO}}_2{\mathrm{F}}_2+{\mathrm{H}}_2\mathrm{O}⟶{\mathrm{XeO}}_3+2\mathrm{HF}\end{array}$
Thus oxidation state is the same +6
Hence the ${\mathrm{XeF}}_6$ does not show a redox reaction.

Thus, the compounds among the following whose hydrolysis is a non-redox reaction,

${\mathrm{XeF}}_6, {\mathrm{XeO}}_2{\mathrm{F}}_2,{ \mathrm{XeOF}}_4$