Find the number of compounds where $d_{x^2-y^2}$ orbitals will not take part in hybridisation.

(a) $\left[\mathrm{Pt}\left({\mathrm{NH}}_3\right)\mathrm{Cl}\left({\mathrm{H}}_2\mathrm{O}\right)\mathrm{Br}\right]$

(b) ${\mathrm{SF}}_4$

(c) ${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_4\right]}^{2+}$

(d) $\left[{\mathrm{XeO}}_3{\mathrm{F}}_2\right]$

(e) $\left[{\mathrm{XeO}}_2{\mathrm{F}}_2\right]$

(F) ${\left[\mathrm{Co}(en{)}_3\right]}^{3+}$

(g) $\left[\mathrm{Fe}(\mathrm{CO}{)}_5\right]$

(h) ${\mathrm{POCl}}_3$

(I) ${\mathrm{XeF}}_4$

(j) ${\mathrm{XeO}}_6^{4-}$

The compounds where  $d_{x^2-y^2}$ orbitals take part in hybridization are $\left[\mathrm{Pt}\left({\mathrm{NH}}_3\right)\mathrm{Cl}\left({\mathrm{H}}_2\mathrm{O}\right)\mathrm{Br}\right]$, ${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_4\right]}^{2+}$, ${\left[\mathrm{Co}(en{)}_3\right]}^{3+}$, ${\mathrm{XeF}}_4$and   ${\mathrm{XeO}}_6^{4-}$, The compounds in which it will not take part are,

${\mathrm{SF}}_4$, $\left[{\mathrm{XeO}}_3{\mathrm{F}}_2\right]$ , $\left[{\mathrm{XeO}}_2{\mathrm{F}}_2\right]$, $\left[\mathrm{Fe}(\mathrm{CO}{)}_5\right]$, ${\mathrm{POCl}}_3$

Hence correct answer is 0005.