Find the number of molecules which are planar

(a) ${\mathrm{ClF}}_3$ (b) ${\mathrm{SF}}_4$

(c)  ${\mathrm{XeF}}_6$ (d) ${\mathrm{XeF}}_2$

(e) ${\mathrm{XeF}}_4$ (f) ${\mathrm{H}}_2\mathrm{O}$

(g)  ${\mathrm{H}}_2\mathrm{S}$ (h) ${\mathrm{NH}}_3$

(i)  ${\mathrm{PH}}_3$ (j) ${\mathrm{PCl}}_5$

(k) ${\mathrm{PCl}}_3$ (l) ${\mathrm{OCl}}_2$

 

${\mathrm{ClF}}_3$,${\mathrm{XeF}}_2$,${\mathrm{XeF}}_4$,${\mathrm{H}}_2\mathrm{O}$,${\mathrm{H}}_2\mathrm{S}$,${\mathrm{PH}}_3$  has a square planar form. Because Both bond pairs and total lone pairs of electrons are present on the centre atom. It goes through many hybridizations, producing square planar molecular geometry and octahedral electron geometry.$a,d,e,f,g,l$